2x^2=17/3x+1

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Solution for 2x^2=17/3x+1 equation: 


x in (-oo:+oo)

2*x^2 = (17/3)*x+1 // - (17/3)*x+1

2*x^2-((17/3)*x)-1 = 0

2*x^2+(-17/3)*x-1 = 0

2*x^2-17/3*x-1 = 0

DELTA = (-17/3)^2-(-1*2*4)

DELTA = 361/9

DELTA > 0

x = ((361/9)^(1/2)+17/3)/(2*2) or x = (17/3-(361/9)^(1/2))/(2*2)

x = 3 or x = -1/6

x in { -1/6, 3 }

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